Question

plz solve these equaction by subsitution method

Answer 1

x=0
y=0
x will be
$\sqrt{ - 3y \div \sqrt{2 - } }$

Answer 2

$\sqrt{2} x + \sqrt{3} y = 0 \: \: \: \: \: \: ....(1) \\ \sqrt{3} x - \sqrt{8}y = 0 \: \: \: \: \: \: .... (2) \\ Using \: equation \: (1), we \: get \: \\ \sqrt{2} x = - \sqrt{3} y \\ x = \frac{ - \sqrt{3} y}{ \sqrt{2 } } \: \: \: \: \: \: ..(3)\\ Putting \: this \: in \: equation \: (2), \: we \: get \\ \sqrt{3}( \frac{ - \sqrt{3}y }{ \sqrt{2} }) - \sqrt{8}y = 0 \\ \frac{ - 3y}{ \sqrt{2} } - \sqrt{8}y = 0 \\ y (\frac{ - 3}{ \sqrt{2} } - \sqrt{8} ) = 0 \\ y( \frac{ - 3 - 4}{ \sqrt{3} }) = 0 \\ y( \frac{ - 7}{ \sqrt{3} } ) = 0 \\ y = 0 \\ Putting \: the \: value \: of \: y = 0 \: \: in \: equation \: (3), \: we \: get \\ x = \frac{ - \sqrt{3}(0) }{ \sqrt{2} }= 0$