Question

plz solve these
i am really worried cuz i have to submit them before 2:00 so plz solve these..​

Answer 1

Answer:

acceleration =slope of v t graph

so in graph 1 the object is under constant acceleration for some time and then acceleration become zero since slope becomes zero (ie line become parallel to x axis so slope is tan (angle between line and x axis)=tan 0=0)

In graph 2 acceleration for first 5 second=100/5=20m/s^2

V=u+at=0+20×5=100 m/s (u is initial velocity which is zero)

deceleration in last 5 second =-100/(20-15)= -20

TOTAL DISTANCE=AREA UNDER VELOCITY TIME GRAPH

=(1/2×100×5)+100×(15-5)+1/2×100×(20-15)

=1500 m

hope it helps you brother

next time on try and do maximum yourself

ont then can your skill improve

hope you will keep that in mind

Good luck

Answer 2

Answer:

nzjs sjsjs sooao xioemdsk qkqk xks aklalan kz kak kakka kexkx agw