plz solve these mcqs
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Answer:
(1) - c- 1-bromo-2- methylbutane
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Explanation:
Given
Givenn=50turns, R=0.5m, I=5A,
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B=
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2R
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B=
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.5
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7 ×50×5
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7 ×50×5
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7 ×50×5 =3.14×10
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7 ×50×5 =3.14×10 −3
Givenn=50turns, R=0.5m, I=5A, According to Bio-sawart Law magnetic flux density is given by B⇒B= 2Rμ 0 nI ⇒B= 2×0.54π×10 −7 ×50×5 =3.14×10 −3 T(◍•ᴗ•◍)❤
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