Question

Plz Solve these question............✌️​

Answer 1

(vi)√1+sin a/1-sina

we will first rationalise it

√1+sin a× 1+sin a/1-sin a × 1+sin a

√(1+sin a )²/1²-sin²a

square and root will be cancelled in the nr.

1+sina /√cos²a                                              .....        (sin²a+cos²a=1)identity

1+sin a /cos a = lhs

now rhs

sec a + tan a      (tan a =sina /cosa)

1/cos a+ sin a/cos a

1+sin a/ cos a =rhs

hence LHS = RHS

(vii) SinA-2sin³A/2cos³A- cosA

SinA(1-2sin^2A)/(2cos^2A- 1)cosA

then, cancel (1-2sin^2A)/(2cos^2A- 1)

u will get sinA/cosA= tanA

sorry I forgot to add theta

hope this helps you.

pls mark as brainliest.

Answer 2

✨HOPE IT HELPS✨

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