plz solve these questions
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It is eessy X is75
exterior angle property outer angle is equal to both inner angle
exterior angle property outer angle is equal to both inner angle
maroof1:
plz explain
if inner angle is 50 we have to find y then by exterior angle property we will subtract exterior angle from one inner angle then we get answer of y
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(i) AngleDCB and AngleACB are on the line so they for 180°angle
Therefore ifAngleDCB=125°then
AngleACB is of 55°
AngleACB+ AngleCAB+AngleABC=180°
55°+50°+x=180°
X=180°-105
X=75°
Therefore AngleABC =75°
(ii) AngleDBC and AngleABC are on straight line
Therefore there total is180°
Therefore if AngleDBC is120
Then AngleABC =60°
Now
AngleACB +AngleABC +AngleCAB =180°
x+60°+2x=180°
3x=120°
x=40°
Therefore AngleACB =40°
and AngleCAB =80°
HOPE IT'S HELPFUL!!!!
PLZZZ MARK AS BRAINLIEST....
Therefore ifAngleDCB=125°then
AngleACB is of 55°
AngleACB+ AngleCAB+AngleABC=180°
55°+50°+x=180°
X=180°-105
X=75°
Therefore AngleABC =75°
(ii) AngleDBC and AngleABC are on straight line
Therefore there total is180°
Therefore if AngleDBC is120
Then AngleABC =60°
Now
AngleACB +AngleABC +AngleCAB =180°
x+60°+2x=180°
3x=120°
x=40°
Therefore AngleACB =40°
and AngleCAB =80°
HOPE IT'S HELPFUL!!!!
PLZZZ MARK AS BRAINLIEST....
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