plz solve these questions
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Heya User,
15 --> 0 < x < 9 => [ 12 + 0 ] < f(x) < [ 12 + 9 ]
=> 12 < f(x) < 21 <-- ANS..
16 --> (b) Symmetric Relation
17 --> Let the nth term be [ xp + c ]
Then, ∑(xp + c) = x/2[p(p+1)] + pc
=> ∑(xp + c) = [ xp² + xp + 2pc ]/2 ---> (i)
Comparing (i) with 2 [3p² + 4p] -->
---> x = 6;
---> [ x + 2c ] = 8
=> 6 + 2c = 8
=> c = 1;
Hence, nth term = [ 6n + 1 ]
17 --> Tn = 5^n
.'. 10th term is 5^10
18 --> a = 1/4
-------> r = (-2)
===> T5 = 1/4 * 16 = 4 <-- Ans
15 --> 0 < x < 9 => [ 12 + 0 ] < f(x) < [ 12 + 9 ]
=> 12 < f(x) < 21 <-- ANS..
16 --> (b) Symmetric Relation
17 --> Let the nth term be [ xp + c ]
Then, ∑(xp + c) = x/2[p(p+1)] + pc
=> ∑(xp + c) = [ xp² + xp + 2pc ]/2 ---> (i)
Comparing (i) with 2 [3p² + 4p] -->
---> x = 6;
---> [ x + 2c ] = 8
=> 6 + 2c = 8
=> c = 1;
Hence, nth term = [ 6n + 1 ]
17 --> Tn = 5^n
.'. 10th term is 5^10
18 --> a = 1/4
-------> r = (-2)
===> T5 = 1/4 * 16 = 4 <-- Ans
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