Math, asked by SamadAhmad, 1 year ago

Plz Solve these questions.....

Attachments:

aryandhar7450: What we have to do in these questions
SamadAhmad: u have to factorise them

Answers

Answered by Ashishkumar098
6
<b > Ello!¡

Here's your answer

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• a² + 4a + 4 - b²

= { ( a )² + 2 . a . 2 + ( 2 )² } - b²

= ( a + 2 )² - ( b )²

[ • ( x + y )² = x² + 2xy + y² → Using this identity
Here , x = a , y = 2 ]

= ( a + 2 + b ) ( a + 2 - b ) [ ★ Required answer ]

[ • x² - y² = ( x + y ) ( x - y ) → Using this identity
Here , x = ( a + b ) , y = b ]

_________________________

• a² - b² - 2a - 1

= a² - { ( b )² + 2 . b . 1 + ( 1 )² }

[ • ( x + y )² = x² + 2xy + y² → Using this identity
Here , x = b , y = 1 ]

= ( a )² - ( b + 1 )²

= ( a + b + 1 ) ( a + b - 1 ) [ ★ Required answer ]

[ • x² - y² = ( x + y ) ( x - y ) → Using this identity
Here , x = a , y = ( b + 1 ) ]

_________________________

• x² + 6x + 9 - 4y²

= { ( x )² + 2 . x . 3 + ( 3 )² } - 4y²

= ( x + 3 )² - ( 2y )²

[ • ( a + b )² = a² + 2ab + b² → Using this identity
Here , a = , b = 3 ]

= ( x + 3 + 2y ) ( x + 3 - 2y ) [ ★ Required answer ]

[ • a² - b² = ( a + b ) ( a - b ) → Using this identity
Here , a = ( x + 3 ) , y = 2y ]

_____________________________

Hope it helps!!

SamadAhmad: thanks bro
Ashishkumar098: :)
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