Question

plz solve these questions6x^2 -3 and verify the relation between zeroes and it's coefficients

Answer 1

6x^2-3

=3(2x^2-1) {on taking 3as common}

=(3) (2x^2 -1)

these are it's factors.

alpha=3

beta=√(1/2)

hope it helps.

Answer 2

Answer:

The quadratic polynomial with α and β as zeroes is x2�− (α + β)x + (αβ)

Given zeroes of the polynomial are 3+√5�and 3-√5

Hence the quadratic polynomial is:

x2�− (3+√5 + 3 −√5)x + (3+√5)(3 −√5)

= x2�− 6x + (9 −5)

= x2�− 6x + 4

Thus the quadratic polynomial is ( x2�− 6x + 4).

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