Math, asked by ggggggggg123, 1 year ago

plz solve these two questions.

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Answers

Answered by Anuragkrverma
2
a3+8b3+64c3-24abc
=a3+(2b)3+(4c)3- 3×a+2b+4c
=(a+2b+4c) [a2+(2b)2 +(4c)2 -a×2b-2b×4c-4c×a]
=(a+2b+4c) (a2+4b2+16c2-2ab-8bc-4ca)

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