plz solve these2 questions someone...plzzzz...
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swine I see swing skew I k kg h of us y us tuffs Ru so CH xiii
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Solution no.3)
Current in wire A,i1=8A
Current in wire B,i2=5A
Force exerted on 10cm section of wire A,
B=μ•2i1i21 / 4πr =2×10 to the power -5 T
Attractive force normal to A towards B, because current direction same.
Solution no.4)
Charge,q=1.6×10^-190C
Magnetic field B= 1 N/m
Angle theeta =30°
Velocity V =5×10^7 ms^-1
F=q(vector v × vector B)
=qvB sin theeta
=5×10^7×1.6×10^-19×1×sin 30 °
=8×10^-12×1/2
=4×10^-12N
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