plz solve this 10 pts
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Answered by
1
Answer:
Step-by-step explanation:
CE=16.5m
ED=CE-CD
=16.5-AB
= 16.5-1.5
=15m
in triangle ADE
sin60=DE/AE
√3/2=15/AE
AE=15*2/√3
=30/√3
=10√3m
thus distance of boy from building is 10√3 m ans'
hope it helps
mark as brainliest
Answered by
0
Answer:
your answer
Step-by-step explanation:
CE=16.5m
ED=CE-CD
=16.5-AB
= 16.5-1.5
=15m
in triangle ADE
sin60=DE/AE
√3/2=15/AE
AE=15*2/√3
=30/√3
=10√3m
thus distance of boy from building is 10√3 m ans'
hope it helps
mark as brainliest
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