plz solve this.......13 and 14 no.
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13} We have,
Inner circumference=88m
Let 'r' be its radius.
2πr=88
2*22/7*r=88
r=14m.
Again,
Outer circumference=132m.
Let 'R' be its radius.
2πR=132
R=21m.
Therefore the width of the track
=R-r
=21-14
=7m.
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which chapter this is
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