Question

plz solve this......​

Answer 1

Hêy Fríèñd...

Here is the Solution..

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I Hope This Will Help You ^_^

Answer 2

Hey mate this is your answer.......

In ∆ ABC , tan 60°= AB/AC =√3=h/AC

= AC = h/√3

In ∆ BDC , tan 30°= x/CD = 1/√3 = x/AC

= 1/√3 = x/h √3

= h/3

Now , BE +AE = h

x + 10 = h

h/3 + 10 = h

10 = h - h/3

10 = 3h - h/3

30 = 2h

h = 15m.........

Hope helps u.......