Question

plz solve this ......., ​

Answer 1

Answer:

Midpoint of AC = Midpoint of BD

[Property of a parallelogram that, the diagonals bisect each other]

Midpoint formula:

$\tt{(x,y) = \frac{(x_{1} + x_{2})}{2} , \frac{(y_{1} + y_{2})}{2}}$

A = (-2 , 3)

B = (6 , 7)

C = (8 , 3)

=> {(-2 + 8)/2 , (3 + 3)/2} = {(6 + x)/2 , (7 + y)/2}

=> 3 , 3 = (6 + x)/2 , (7 + y)/2

=> (6 + x)/2 = 3 , (7 + y)/2 = 3

=> 6 + x = 6 , 7 + y = 6

=> x = 0 , y = (-1)

Point = (0 , -1)

Answer (c) (0 , -1)

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Answer 2

Hello buddy

Answer:

Option c

(0,-1)

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