Question

plz solve this.... ​

Answer 1

Answer:

1) y = x^2 tanx

differentiate y with respect to x

dy/dx = x^2.d/dx(tanx) + tanx.d/dx(x^2)

= x^2.(sec^2 x) + tanx.(2x)

=x^2.(sec^2 x) + 2x.tanx

2) y = e^x.(logx)

differentiate y with respect to x

dy/dx = e^x.d/dx(log x) + log x .d/dx(e^x)

= e^x.(1/x) + logx.(e^x)

taking e^x common

= e^x . [ 1/x + log x]

____________________________

HOPE THIS ANSWER WILL HELP U...

Thank you!!