Question

plz solve this.........​

Answer 1

Answer:

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Step-by-step explanation:

Here,,

${(x + 1)}^{4} = {( {x}^{2 } + x - 6)}^{2}$

Now...

${x}^{2} + 2x + 1 = {x}^{2} + x - 6$

here we can't take x as it gets negative value. so... try this as it was a square root....

${x}^{2} + 2x + 1 = - ( {x}^{2} + x - 6)$

now we get two values of x

1. x = -2.5
2. x = 1

But we can't take negative value. So the ans is 1. Also if we place 1 instead of x in the equation we get 4.so,the x= 1 passes the equation.