Math, asked by bazlynn78, 6 months ago

plz solve this....❤​

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Answers

Answered by nooblygeek
1

Answer:

Beena is 12 years old.

Step-by-step explanation:

This question can be solved by a setting up a system of equations.

We know that the sum Beena's age  and one third of her mother's age is 26. We can rewrite this as an equation. If we call Beena's age B and her mother's age M, then the equation becomes

B + \frac{1}{3} M= 26.

We also know that her mother is 30 years older than Beena, this becomes the equation

B+30 = M.

From the second equation, we have the identity M = B+30, which we can substitute into the first equation, hence

B+\frac{1}{3}(B+30) = 26,

which is the same as

B + \frac{1}{3} B + 10 = 26,

subtracting 10 on both sides and combining the B's gives

\frac{4}{3} B = 16

Multiplying both sides by 3 gives

4B = 48,

dividing both sides by 4 gives

B=12.

Hence Beena is 12 years old.

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