Question

plz solve this algebraic expressions equation don't spam otherwise your answer will reported
​

Answer 1

Answer:

3p²q²r² - 2pqr + 7 = 103

Step-by-step explanation:

3p²q²r² - 2pqr + 7 = 3((-3)²(-1)²(2)²) - 2((-3)(-1)(2)) + 7

= 3(9×1×4) - 2(3×2) + 7

= 3(36) - 2 (6) + 7

= 108 - 12 + 7

= 96 + 7

= 103

Answer 2

Answer:

$\color{lime}{1} \color{aqua}{0} \color{red}{3}$

Step-by-step explanation:

Your question:

If p= -3, q= -1 and r= 2, find the value of 3p^2q^2r^2 - 2pqr + 7.

Your answer:

[placing the values as given in question ]

$= 3( - 3 {)}^{2} ( { - 1})^{2} ( {2)}^{2} - 2( - 3)( - 1)(2) + 7$

[ do as given below ]

$= 3 \times 9 \times 1 \times 4 - 2(3)(2) + 7$

[ squaring the numbers:) ]

$= 3 \times 36 - 12 + 7$

[ multiply ]

$= 108 - 5$

$= 103$