Question

plz solve this...
answer = -4​

Answer 1

I hope this will help you

Answer 2

Step-by-step explanation:

here is ur answer mate

$\frac{x - 2}{x + 2} = \: k \\ = > \: k \: + \: \frac{3}{k} \: - 4 \\ = > \: {k}^{2} \: + \: 3 \: - 4k \\ = > \: {k}^{2} \: - 3k \: - \: k \: + 3 \\ = > \: k(k - 3) \: - 1(k - 3) \\ = > k \: = 3 \: or \: 1 \\ let \: k \: = \: 3 \: in \: first \: case \\ \frac{x - 2}{x + 2} = \: 3 \\ x - 2 = \: 3x + 6 \\ - 8 \: = \: 4x \\ x \: = - 2 \\ second \: case \\ \frac{x - 2}{x + 2} = 1 \\ x - 2 = \: x + 2 \\ = 0$