Question

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Answer 1

Given:

⇒ T ≡ ( -1 , 6 ) ≡ ( x , y )

⇒ S ≡ ( -3 , 10 ) ≡ (x₁ , y₁)

⇒ R ≡ ( 6 , - 8) ≡ (x₂, y₂)

To Find:

The ratio in which point T divides line segment SR.

Solution:

According to the picture you attached they have considered the ratio in which T divides SR as m : n

Now applying the section formula :

$\tt{x = \dfrac{mx_1 + nx_2 }{m+n }}\\ \\ Here\ x_1\ and \ x_2\ are\ the\ x \ co-ordinates\ of\ S\ and\ R .\\ \\ \implies -1 =\dfrac{m\times \boxed{\tt{6}}+n\times\boxed{\tt{-3}}}{m+n} \\ \\ \implies -m-n=\boxed{\tt{6m-3n}} \\ \\ \implies -7m = -2n\\ \\ \implies \dfrac{m}{n}=\boxed{\tt{\dfrac{2}{7}}}$

Hope this answer helps.

Answer 2

Answer:

657

1. Step-by-step explanation:
2. first add 60 plus seven then add damm 5 duh!