plz solve this anyone
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rohitrathee30:
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√2+1/√2-1 -√2-1/√2+1 = a+√2b
(√2+1)(√2+1)-(√2-1)(√2-1)/(√2-1)(√2+1) = a+√2b
2+1+2√2-2-1+2√2 = a+√2b
4√2= a+√2b
therefore a=0 b=4
(√2+1)(√2+1)-(√2-1)(√2-1)/(√2-1)(√2+1) = a+√2b
2+1+2√2-2-1+2√2 = a+√2b
4√2= a+√2b
therefore a=0 b=4
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a = 0 and b= 4
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