Plz solve this Class 9 Chapter Triangles
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Using Alternate angle theorem,
when line AB || line CD,
angle EDC = 52°
Now, Sum of all angles of triangle = 180°
40° + 52° + x = 180°
x = 88°
HOPE THIS HELPS YOU OUT....
Answered by
2
Step-by-step explanation:
As AB // DC
Given,
Angle BAD = 52°
Angle BAD = Angle CDE (Alternative interior angles)
So, Angle CDE = 52°
In ∆le EDC
Angle DEC + Angle CDE + Angle DCE = 180°(Sum of angles of a ∆le)
x°+52°+40° = 180°
x° = 180°-92°
x° = 88°
Angle DEC => x° = 88°
Hope it helps you........
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