Question

plz solve this correctly​

Answer 1

Answer:

I am trying my best to solve the ans

Answer 2

Step-by-step explanation:

Q

$\frac{6x + 1}{3} + 1 = \frac{x - 3}{6} \\ \frac{6x + 1}{3} - \frac{x - 3}{6} = - 1 \\ \frac{2(6x + 1) - (x - 3)}{6} = - 1 \\ \frac{12x + 2 - x + 3}{6} = - 1 \\ \frac{11x + 5}{6} = - 1 \\ 11x + 5 = - 5 \times 6 \\ 11x = - 30 - 5 \\ x = \frac{ - 35}{11}$