Question

plz solve this:-

(cosecA-SinA)(SecA+TanA)(TanA+CotA)=1​

Answer 1

Answer:

$l.h.s. = ( \frac{1}{ \sin\alpha } - \sin\alpha )( \frac{1}{cos \alpha} + \frac{sin \alpha }{cos \alpha } )( \frac{sin \alpha }{cos \alpha } + \frac{cos \alpha }{sin \alpha } ) \\ \\ = (\frac{1 - {sin}^{2} \alpha }{sin \alpha } )( \frac{1 + sin \alpha }{cos \alpha } )( \frac{ {sin}^{2} \alpha + {cos}^{2} \alpha }{sin \alpha .cos \alpha } ) \\ \\ = (\frac{ {cos}^{2} \alpha }{sin \alpha } )( \frac{1 + sin \alpha }{cos \alpha } )( \frac{1}{sin \alpha .cos \alpha } ) \\ \\ = \frac{ 1 + sin \alpha }{ {sin}^{2} \alpha }$

Answer 2

Step-by-step explanation:

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