Question

Plz solve this equation​

Answer 1

Answer:

The value of the given equation i. e. x = -1

Answer 2

$\huge\mathbf\purple{answer~~↓~↓}$

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To solve :

$\sf \frac{3x - 7}{x - 4} + \frac{2x + 5}{x + 2} = 5 \\ \\ \sf \frac{(3x - 7)(x + 2) + (2x + 5)(x - 4)}{(x - 4)(x + 2)} = 5 \\ \\ \sf \frac{( {3x}^{2} + 6x - 7x - 14) + ( {2x}^{2} - 8x + 5x - 20) }{ {x}^{2} + 2x - 4x - 8 } = 5 \\ \\ \sf \frac{( {3x}^{2} - x - 14) + ( {2x}^{2} - 3x - 20) }{ {x}^{2} - 2x - 8} = 5 \\ \\ \sf By \: cross \: multiplication, \: we \: get \\ \\\ \sf ( {3x}^{2} - x - 14) + ( {2x}^{2} - 3x - 20) = 5({x}^{2} - 2x - 8) \\ \\ \sf {5x}^{2} - 4x - 34 = {5x}^{2} - 10x - 40 \\ \\ \sf {5x}^{2} - {5x}^{2} - 4x + 10x = - 40 + 34 \\ \\ \sf 6x = - 6 \\ \\ \sf x = \frac{ - 6}{6} \\ \\ \sf x = - 1$

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$\huge\mathbf\purple{Hope~it~helps..!!}$