Math, asked by Sunilvishyan71, 4 months ago

plz solve this equation ​

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Answers

Answered by ssubham96029
1

sum of=

8a+3ab-2b+7 +(4a+5b-28ab-15)

=8a+4a+3ab-28ab-2b+5b+7-15

=12a-25ab+3b-8

difference of=

2a-4b+3ab+5-(3a+6b-9ab+12)

=2a-4b+3ab+5-3a-6b+9ab-12

=2a-3a-6b-4b+3ab+9ab+5-12

= -a-10b+12ab-7

subtraction=

-a-10b+12ab-7-(12a -25ab+3b-8)

=-a-10b+12ab-7-12a+25ab-3b+8

=-a-12a-10b-3b+12ab+25ab-7+8

=-13a-13b+37ab-1

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