Math, asked by sumit8928, 2 months ago

Plz solve this Equation?

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Answers

Answered by Anonymous
4

Given Equation

 \sf \to \:  {4}^{x}  \times  {2}^{y}  = 128

 \sf \to \:  {3}^{3x + 2y}  =  {9}^{xy}

Now Take

 \sf \to \:  {4}^{x}  \times  {2}^{y}  = 128

Using Exponential Properties

 \sf \to \:  {2}^{2x}  \times  {2}^{y}  = 128

\sf \to \:  {2}^{2x + y}  = 128

\sf \to \:  {2}^{2x + y} = (2)^{7}

We get

 \sf \to2x + y = 7

Now Take

\sf \to \:  {3}^{3x + 2y}  =  {9}^{xy}

\sf \to \:  {3}^{3x + 2y}  =  {3}^{2xy}

We get

 \sf \to \: 3x + 2y = xy

Answer

\sf \to2x + y = 7

 \sf \to \: 3x + 2y = xy

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