Question

plz solve this equation and find the value of t​

Answer 1

Answer:

t=-30

Step-by-step explanation:

t$20t+40+5(t^{2}+4t+4)=20t+5t^{2} \\ = \\ 20t+40+5t^{2} +20t+20= 20t+5t^{2} \\= \\20t=-20-40+5t^{2} -5t^{2} +20t-20t\\=\\20t=-40-20\\=\\t=-60/20\\=\\t=-30$