Question

plz..solve this Equation.if you will solve it then I will mark you as brainliest.plz..plz..solve it Quickly​

Answer 1

Answer:

x=2 or -4/3

Step-by-step explanation:

$\frac{1}{x + 2} + \frac{1}{x} = \frac{3}{4} \\ = > \frac{x + (x + 2) }{x(x + 2)} = \frac{3}{4} \\ = > \frac{2x + 2}{ {x}^{2} + 2x} = \frac{3}{4} \\ = > 4(2x + 2) = 3( {x}^{2} + 2x) \\ = > 8x + 8 = 3 {x}^{2} + 6x \\ = > 3 {x}^{2} + 6x - 8x - 8 = 0 \\ = > 3 {x}^{2} - 2x - 8 = 0 \\ = > 3 {x}^{2} - 6x + 4x - 8 = 0 \\ = > 3x(x - 2) + 4(x - 2) = 0 \\ = > (x - 2)(3x + 4) = 0 \\ = > x - 2 = 0 \: \: or \: 3x + 4 = 0 \\ x = 2 \: \: \: or \: \: x = \frac{ - 4}{3}$