Question

plz solve this equation. It's IIT type question so plz don't apply basic equation solving skills. and plz no scam.​

Answer 1

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Step-by-step explanation:

(5x-64)/(x-13) - (2x-11)/(x-6) = (4x-55)/(x-14) - (x-6)/(x-7)

we substract 3 from both sides,

(5x-64)/(x-13) - (2x-11)/(x-6) - 3 = (4x-55)/(x-14) - (x-6)/(x-7) - 3

● (5x-64)/(x-13) - (2x-11)/(x-6) - 5 + 2 = (4x-55)/(x-14) - (x-6)/(x-7) - 4 + 1

● (5x-64)/(x-13) -5 - (2x-11)/(x-6) +2 = (4x-55)/(x-14) - 4 - (x-6)/(x-7) + 1

● {(5x-64) - 5(x-13)}/(x-13) + {-(2x-11) +2(x-6)}/(x-6) = {(4x-55) - 4 (x-14)}/(x-14) + {-(x-6) + 1(x-7)}/(x-7)

● (5x-64-5x+65)/(x-13) + (-2x+11+2x-12)/(x-6) = (4x-55-4x+56)/(x-14) + (-x+6+x-7)/(x-7)

● 1/(x-13) - 1/(x-6) = 1/(x-14) - 1/(x-7)

● 1/(x-13) - 1/(x-14) = 1/(x-6) - 1/(x-7)

● ((x-14) - (x-13))/(x-13)(x-14) = ((x-7) - (x-6))/(x-6)(x-7)

● (x-14-x+13)/(x-13)(x-14) = (x-7-x+6)/(x-6)(x-7)

● -1/(x-13)(x-14) = -1/(x-6)(x-7)

● 1/(x-13)(x-14) = 1/(x-6)(x-7)

● (x-13)(x-14) = (x-6)(x-7)

● x^2-27x+182 = x^2-13x+42

● -27x+182 = -13x + 42

● -27x + 13x = 42 - 182

● -14x = -140

● x = -140/-14 = 10