Question

plz solve this!!!! factorise​

Answer 1

Answer:

$\sqrt{2}x^{2} + 3x + \sqrt{2} \\ = \sqrt{2} {x}^{2} + 2x + x + \sqrt{2} \\ = \sqrt{2} x(x + \sqrt{2} ) + 1(x + \sqrt{2} ) \\ = (x + \sqrt{2} )( \sqrt{2} x + 1)$

This should be correct answer

Answer 2

$\sqrt{2} {x}^{2} + 3x + \sqrt{2}$

$\sqrt{2} {x}^{2} + 2x + x + \sqrt{2}$

$\sqrt{2} x (x + \sqrt{2} ) + 1(x + \sqrt{2} )$

$(\sqrt{2} x + 1)(x + \sqrt{2} )$

Now,

x= $\frac{-1}{\sqrt{2}}$ . . .and. . . x= $-\sqrt{2}$