Plz solve this.. fast...
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Answer:
Option B is the correct answer.
Explanation:
=> We know that ,
For. 2A --> product
By Rate law:-
Rate = - ½ {d/dt}[A] = K [A]²
since its of second order
-------------------
Given.
=> Rate constant = K = 9× 10^-5 M L^-1s^-1
=> A = 0.25 M/L
So,
Rate = K [A] ²
= (9×10^-5 )× (0.25)²
= 0.5625 × 10^-5
= 5.6 × 10^-6 M/L s ( answer)
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