Question

plz solve this fast

Answer 1

Hi.

Here is your answer---

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According to the Question,a meter Rule is pivoted at the Center. i.e. at the 50 cm mark.

Thus, W1( First Weights) = 50 gf.

It will be suspended at 0 cm mark,

thus distance(d1) = (50 - 0)
                       = 50 cm from the centre

   W2 = 100 gf.

Let the distance at which the weights of 100 gf will be suspended on the other end of the Meter rule be d.


According to the Principle of moments,

           Anti-Clockwise moments = Clockwise Moments.
                                   W1 × d1 = W2 × d
                                   50 × 50 = 100 × d
                                            d = 25 cm.

Thus, the weights of 100 gf will be suspended at the distance of 25 cm from the Center on the other side of the meter Rule.

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Hope it helps.

Have a nice day.