Plz solve this fast.
A bag contains 3 red balls and 5black balls. A ball is drwn at random from the bag. what is the probability that the ball drawn is I) red ii) not red ?
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Answered by
7
probability of getting red ball is 3/8
probability of getting black ball is 5/8
please mark it as a branliest answer
probability of getting black ball is 5/8
please mark it as a branliest answer
Answered by
4
Hi there,
Here is your answer :
______________________________
I) Total number of balls in the bag = 3 + 5 = 8
Total outcomes = 8
Favourable outcomes = 3
Probability of getting a red card,
= P( E) = Favourable outcomes / Total outcomes
= 3/8
ii) If p( E~) is the probability of getting not a red ball, then
p(E) + p( E~) = 1
P(E~) = 1 - P(E~)
= 1 - 3/8
= 5/8
HOPE THIS HELPS U...
Here is your answer :
______________________________
I) Total number of balls in the bag = 3 + 5 = 8
Total outcomes = 8
Favourable outcomes = 3
Probability of getting a red card,
= P( E) = Favourable outcomes / Total outcomes
= 3/8
ii) If p( E~) is the probability of getting not a red ball, then
p(E) + p( E~) = 1
P(E~) = 1 - P(E~)
= 1 - 3/8
= 5/8
HOPE THIS HELPS U...
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