Question

plz solve this fast...best will be brainliest!!!!​

Answer 1

Answer:

2/5 &-1,go through following attachment

Answer 2

Answer:

(1) 2/5.

(2) -1

Step-by-step explanation:

(1)  $\lim_{x \to 0 } [\frac{x^{2}+3x+2}{2x^{2}+x+5} ] = \frac{0^{2}+3(0)+2}{2*0^{2}+0+5}=\frac{2}{5}$

(2)  $\lim_{x \to 1} [\frac{x^{2}-3x+2}{x-1} ] = \lim_{x \to 1} [\frac{(x-1)(x-2)}{x-1} ]$

                                 $= \lim_{x \to 1} (x-2) =1-2=-1.$