Question

Plz solve this fast
Help me

Answer 1

$\frac{6}{x} - \frac{2}{x - 1} = \frac{1}{x - 2} \\ taking \: lcm \\ \frac{6(x - 1) - 2x}{x(x - 1)} = \frac{1}{x - 2} \\ \frac{4x - 6}{ {x}^{2} - x } = \frac{1}{x - 2} \\ cross \: multiply \\ 4 {x}^{2} - 8x - 6x + 12 = {x}^{2} - x \\ 3 {x}^{2} - 13x + 12 = 0 \\ 3 {x}^{2} - 9x - 4x + 12 = 0 \\ 3x(x - 3) - 4(x - 3) \\(3x - 4)(x - 3) \\ x = 3 \: or \: x = \frac{4}{3}$

Answer 2

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