Question

Plz solve this fast it is cbse boards 2019 paper​

Answer 1

1,total surface area of is block =TSA of cube +CSA of hemisphere-area of base of circle

$6( {a}^{2} )+ 2\pi{r}^{2} - \pi {r}^{2}$

6(6^2)+2×22/7×2.1×2.1-22/7×2.1×2.1