plz solve this for me ....
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hope its help you.......
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pista1:
thank you so much.
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Let 'a' be the first term & 'd' be the common difference of an A.P
[a (n)th = a+ (n-1)d]
15th term of an a.p
a(15) = a+14d
8th term of an a.p
a8 = a+7d
A.T.Q
a15= a8 + 7
a+14d = a+7d+7
14d-7d= 7
7d= 7
d= 7/7
d=1
common difference (d) = 1
[a (n)th = a+ (n-1)d]
15th term of an a.p
a(15) = a+14d
8th term of an a.p
a8 = a+7d
A.T.Q
a15= a8 + 7
a+14d = a+7d+7
14d-7d= 7
7d= 7
d= 7/7
d=1
common difference (d) = 1
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