Math, asked by 2004muskansoni, 6 months ago

plz solve this for me ...​

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Answers

Answered by chauhanaaditya43
1

Answer:

dhek lo ggggg acha laga too brilliant kar diyo

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Answered by ata55
1

Answer:

secθ + tanθ = m -----> 1

secθ - tanθ = 1/m -------->2

Add 1 and 2

2secθ = m + 1/m

2secθ = m² + 1/m

secθ = m² + 1

----------

2m

cosθ = m² + 1

----------

2m ( secθ = 1/cosθ )

Subtract 1 and 2

2tanθ = m - 1/m

2tanθ = m² - 1/m

tanθ = m² - 1

----------

2m

sinθ = tanθ × cosθ

sinθ = 2m m² - 1

---------- × ----------- (Cancel out 2m)

m²-1 2m

sinθ = m² - 1

------------

m² + 1

Hence Proved.

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