Question

Plz solve this
How many 4-digit numbers greater than 2300 can be formed with the digits 0,
1, 2, 3, 4, 5 and 6, no digit being repeated in any number?​

Answer 1

ANSWER

There are two cases, (i)First digit is greater than 2

(ii)First digit is 2

Case :(i) First digit can be chosen from 3,4,5,6 so 4 possibilities,

then next 3 digits can be selected from any 6 digits.

=4×6×5×4=480

Case :(ii) First digit is 2, second digit starts from 3, so it can be 3,4,5,6 so 4 possibilities.

Now if any one digit of third and fourth digit can be 0 as no digit is repeated so it will be surely greater than 2300. So last two digits can be selected from any 5 digits.

=1×4×5×4=80

∴ Total=480+80=560.

IF THIS HELPS , THEN PLEASE FOLLOW ME AND PLEASE MARK THIS AS THE BRAINLIEST