plz solve this.
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Hii ☺ !!
Here is your answer ✓ ✓ ✓ ✓
Side of square ( S ) = 60 cm
Therefore,
Perimeter of square = 4 × Side = 4 × 60 = 240 cm.
And,
Area of square = (Side)² = (60)² = 3600 cm².
Length of rectangle = 80 cm.
Let Breadth of rectangle be X cm.
It is given that perimeter of rectangle is equal to the perimeter of square .
Therefore,
Perimeter of rectangle = Perimeter of square.
2 ( Length+ Breadth ) = 240
2 ( 80 + X ) = 240
160 + 2x = 240
2x = 240 - 160
2x = 80
x = 40 cm.
Breadth of rectangle = X = 40 cm.
Therefore,
Area of rectangle = Length × Breadth = 80 × 40 = 3200 cm².
Hence,
Area of square is more than the area of rectangle by 400 cm².
☺ Hope it will help you ☺
BySaniyaAnwar
#BeBrainly
Here is your answer ✓ ✓ ✓ ✓
Side of square ( S ) = 60 cm
Therefore,
Perimeter of square = 4 × Side = 4 × 60 = 240 cm.
And,
Area of square = (Side)² = (60)² = 3600 cm².
Length of rectangle = 80 cm.
Let Breadth of rectangle be X cm.
It is given that perimeter of rectangle is equal to the perimeter of square .
Therefore,
Perimeter of rectangle = Perimeter of square.
2 ( Length+ Breadth ) = 240
2 ( 80 + X ) = 240
160 + 2x = 240
2x = 240 - 160
2x = 80
x = 40 cm.
Breadth of rectangle = X = 40 cm.
Therefore,
Area of rectangle = Length × Breadth = 80 × 40 = 3200 cm².
Hence,
Area of square is more than the area of rectangle by 400 cm².
☺ Hope it will help you ☺
BySaniyaAnwar
#BeBrainly
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