plz solve this i hope u will help ne
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x^4 + 1/x^4 = 119.
This equation can be written as
x^4 + 1/x^4 + 2 = 121
(x^2 + 1/x^2)^2 = (11)^2
x^2 + 1/x^2 = 11 ------ (1)
Now,
x^2 + 1/x^2 - 2 = 9
(x - 1/x)^2 = (3)^2
x - 1/x = 3 ------ (2)
Now,
On cubing both sides, we get
(x - 1/x)^3 = (3)^3
x^3 - 1/x^3 - 3 * x * 1/x(x - 1/x) = 27
x^3 - 1/x^3 - 3 * (x - 1/x) = 27
x^3 - 1/x^3 - 3(3) = 27
x^3 - 1/x^3 = 27 + 9
x^3 - 1/x^3 = 36.
Hope this helps!
This equation can be written as
x^4 + 1/x^4 + 2 = 121
(x^2 + 1/x^2)^2 = (11)^2
x^2 + 1/x^2 = 11 ------ (1)
Now,
x^2 + 1/x^2 - 2 = 9
(x - 1/x)^2 = (3)^2
x - 1/x = 3 ------ (2)
Now,
On cubing both sides, we get
(x - 1/x)^3 = (3)^3
x^3 - 1/x^3 - 3 * x * 1/x(x - 1/x) = 27
x^3 - 1/x^3 - 3 * (x - 1/x) = 27
x^3 - 1/x^3 - 3(3) = 27
x^3 - 1/x^3 = 27 + 9
x^3 - 1/x^3 = 36.
Hope this helps!
siddhartharao77:
:-)
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Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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