Question

plz solve this

i need solution​

Answer 1

$\dfrac {x}{y}+\dfrac {y}{x}=-1\\\\\\\dfrac {x^2+y^2}{xy}=-1\\\\\\x^2+y^2=-xy\\\\\\x^2+xy+y^2=0$

Then,

$x^3-y^3=(x-y)(x^2+xy+y^2)\\\\\\x^3-y^3=\mathbf {0}$

Answer 2

Answer:

HERE IS THE SOLUTION MATE.

Step-by-step explanation:

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