plz solve this, I need this. plz help me
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HELLO.........FRIEND!!
THE ANSWER IS HERE,
Let the theta be a form my convenience .
=> Sin10a = Cos8a.
We know that Cosx = Sin (90-x).
=> Sin10a = Sin(90-8a).
=> 10a =90-8a
=> 18a=90.
=>a =90/18
=> a=5.
From the question,
=> Tan9a
=> Tan9 (5)
=> Tan45
=> 1.
:-)Hope it helps u.
THE ANSWER IS HERE,
Let the theta be a form my convenience .
=> Sin10a = Cos8a.
We know that Cosx = Sin (90-x).
=> Sin10a = Sin(90-8a).
=> 10a =90-8a
=> 18a=90.
=>a =90/18
=> a=5.
From the question,
=> Tan9a
=> Tan9 (5)
=> Tan45
=> 1.
:-)Hope it helps u.
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