plz solve this i need urgent.
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Hello Mate
Answer:
In Tri. ABP and Tri. CDP
Angle P = Angle P (Common)
Angle A = Angle C (alt Angles) (this angles are equal because of AB ll CD)
Therefore Tri. ABP similar to Tri. CDP by AA
Therefore AB/CD = AP/CP = DP/BP
Now,
Ar of ABP/ Ar of CDP = AB^2/CD^2 (Ar. of triangle's are equal to their corresponding sides)
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