plz solve this I request you
Attachments:
Answers
Answered by
5
given:
m+n=7_______1)
mn=12_______2)
m-n=?
from 2) we have:
m=12/n.........3)
from 1) we have :
m=7-n..........4)
now according to eq 3 & 4 we have:
=>12/n=7-n
=>12/n+n=7
=>(12+n^2)/n=7
=>n^2 +12 =7n
=>n^2-7n+12=0
=>n^2-4n-3n+12=0
=>n(n-4)-3(n-4)=0
=>n=4 or n=3
0n putting this value in eq 3 we have:
m=3 0r m=4
now,
m-n=(4-3)=1
or
(m-n)=(3-4)=-1
m+n=7_______1)
mn=12_______2)
m-n=?
from 2) we have:
m=12/n.........3)
from 1) we have :
m=7-n..........4)
now according to eq 3 & 4 we have:
=>12/n=7-n
=>12/n+n=7
=>(12+n^2)/n=7
=>n^2 +12 =7n
=>n^2-7n+12=0
=>n^2-4n-3n+12=0
=>n(n-4)-3(n-4)=0
=>n=4 or n=3
0n putting this value in eq 3 we have:
m=3 0r m=4
now,
m-n=(4-3)=1
or
(m-n)=(3-4)=-1
Answered by
4
given,
m+n=7mn=12
we know that ,
(m-n)² = (m+n)² -4mn.
(m-n)²= 7² -4*12
(m-n)²= 49-48
(m-n)²= 1
m-n= +1 or -1!
Hope it hepled you!
m+n=7mn=12
we know that ,
(m-n)² = (m+n)² -4mn.
(m-n)²= 7² -4*12
(m-n)²= 49-48
(m-n)²= 1
m-n= +1 or -1!
Hope it hepled you!
Similar questions