Question

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Answer 1

Answer:

Step-by-step explanation:

Tangents drawn from an external point to a circle are equal.

⇒ AD = AF, BD = BE, CE = CF.

 

Let AD = AF = a  

BD = BE = b  

CE = CF = c  

 

AB = AD + DB = a + b = 8 -------- (1)

BC = BE + EC = b + c = 10 -------- (2)

AC = AF + FC = a + b = 12 -------- (3)

 

Adding (1), (2) and (3), we get

2 (a + b + c) = 30

⇒ (a + b + c) = 15 -------- (4)

 

Subtracting (1) from (4), we get c = 7

Subtracting (2) from (4), we get a = 5

Subtracting (3) from (4), we get b = 3

 

Therefore, AD = a = 5 cm, BE = b = 3 cm, CF = c = 7 cm

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Answer 2

 Tangents drawn from an external point to a circle are equal. ⇒ AD = AF, BD = BE, CE = CF.  Let AD = AF = a  BD = BE = b  CE = CF = c   AB = AD + DB = a + b = 8 -------- (1) BC = BE + EC = b + c = 10 -------- (2) AC = AF + FC = a + b = 12 -------- (3)   Adding (1), (2) and (3), we get 2 (a + b + c) = 30 ⇒ (a + b + c) = 15 -------- (4)   Subtracting (1) from (4), we get c = 7 Subtracting (2) from (4), we get a = 5 Subtracting (3) from (4), we get b = 3   Therefore, AD = a = 5 cm, BE = b = 3 cm, CF = c = 7 cm

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