Question

plz solve this if u can​

Answer 1

Answer:

a=5; b=1

Step-by-step explanation:

If then the pair of linear equations has infinitely many solutions.

a1/a2=b1/b2=c1/c2

a1=2

a2=a-b

b1=3

b2=a+b

c1=7

c2=3a+b-2

a1/a2=b1/b2

2/a-b=3/a+b

by Cross multiply we get

2(a+b)=3(a-b)

2a+2b=3a-3b

5b=a

now from b1/b2=c1/c2

[3/(a+b)]=[7/(3a+b-2)]

by Cross multiply we get

3(3a+b-2)=7(a+b)

9a+3b-6=7a+7b

9a-7a=7b-3b+6

2a=4b+6

2*(5b)=4b+6    as a=5b

10b-4b=6

6b=6

b=1

a=5*b=5*1

a=5

Answer 2

$\frac{a - b}{2} = \frac{a + b}{3} = \frac{3a + b - 2}{7}$

$3a - 3b = 2a + 2b \\ a = 5b$

and

$7a + 7b = 9a + 3b - 6 \\ 2a = 4b + 6 \\ 2(5b) = 4b + 6 \\ 5b = 2b + 3 \\ 3b = 3 \\ b = 1 \\ a = 5$