Question

plz solve this in n.b class 9th​

Answer 1

Answer:

(i) (√10 + 2)( √5 -√3 )

= ( √10*√5 + 2*√5 - √3*√10 - √3*2)

= ( √50 + 2√5 - √30 - √6 )

(ii) (4-√2 ) (4+√2 )

= ( 4)^2 - (√2)^2 (a^2 - b^2 = (a - b)(a+ b )

= 16 -2

= 14

(iii) (√5 - √7 ) ( √7 -√5 )

= ( √5*√7 - √7*√7 - √5*√5 + √7*√5 )

= ( √35 - 7 - 5 + √35 )

= ( -12 + 2√35)

= 2 ( -6 + √35)

(iv) ( 5+√2 ) (5+√2)

= (5 +√2 )^2

= (5)^2 + (√2)^2 + 2*5*√2

= 25 + 2 + 10√2

= 27 + 10√2

(v) (√6 + √3)^2

= (√6)^2 + (√3 )^2 + 2*√6*√3

= 6 + 3 + 2√18 .

= 9 + 2√18

= √9 ( √9 + 2√2 ) .

please mark as brainliest .please