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Sides of first triangle = 6 cm, 11 cm, 12 cm
The sides of 2nd triangle are INTEGRAL length. So the sides of 2nd triangle are whole numbers and not (fraction/decimal).
So sides of 2nd triangle can only be ob obtained by multiplying sides of 1st triangle by a non-zero whole number................... (1)
1st and 2nd triangles are similar but NOT congruent. So corresponding sides of the two triangles are NOT equal.
But one of the sides of 2nd triangle is congruent to a side of 1st triangle
So, one of the sides of 2nd triangle is either 6cm, 11cm or 12cm -------- (2)
If we multiply the sides of 1st triangle by 2 then we will get sides of 2nd triangle as 12cm, 22cm & 24cm fulfilling Requirement (1)
In this case 3rd side of 1st triangle is equal to 1st side of 2nd triangle fulfilling Requirement (2)
So perimeter of 2nd triangle = 12+22+24 = 58 cm
The sides of 2nd triangle are INTEGRAL length. So the sides of 2nd triangle are whole numbers and not (fraction/decimal).
So sides of 2nd triangle can only be ob obtained by multiplying sides of 1st triangle by a non-zero whole number................... (1)
1st and 2nd triangles are similar but NOT congruent. So corresponding sides of the two triangles are NOT equal.
But one of the sides of 2nd triangle is congruent to a side of 1st triangle
So, one of the sides of 2nd triangle is either 6cm, 11cm or 12cm -------- (2)
If we multiply the sides of 1st triangle by 2 then we will get sides of 2nd triangle as 12cm, 22cm & 24cm fulfilling Requirement (1)
In this case 3rd side of 1st triangle is equal to 1st side of 2nd triangle fulfilling Requirement (2)
So perimeter of 2nd triangle = 12+22+24 = 58 cm
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